速度为12/20=0.6 km/min 人车所受重力为mg 阻力为0.05mg 所以牵引力为600N(g取10N/kg)
(1)∵当S1闭合S2断开时,串联电路
∴I1=I(R2)=I(R变)
∵当S1断开S2闭合时,串联电路
∴I2=I(R2)=I(R1)
∵P=UI,U=IR
∴P=I²R
又∵R2是定值电阻
∴P2:P2’=I²1R2:I²2R2=I²1:I²=49:144
∴I1:I2=7:12
设总路程为S
V=S÷(0.5S/V1+0.5S/V2)
=S÷[0.5S(1/V1+1/V2)]
=2÷(1/V1+1/V2)
=2V1V2/(V1+V2)
=2×30Km/h×60Km/h÷(30Km/h+60Km/h)=40Km/h