(1)能,距离L2=(V1^2-0)/2a=5^2/(2*5)=2.5m (2)加速时,a1=V0^2/2L=2.5m/s^2,则动摩擦因数为u=F/mg=a/g=0.25.为使粉笔不滑动,则传带对粉笔的作用力范围是:ma-umg<=F<=ma+umg,其中F=ma0.故可得a-ug<=a0<=a+ug.得2.5m/s^2<=a0<=7.5m/s^2i2e物理好资源网(原物理ok网)